Magnetic flux of 12 μWb is linked with a coil and a current of 0.2A passes through it. What will be the self inductance of the coil?

6x 10-5 H 6.7x 10-5 H 6mH 6x 10-6 H

6x 10-5 H

Magnetic flux associated with a coil : Φ =  Li                               Self inductance : L =  Φ/i                                                        = (12x10-6)Wb/ 0.2A                                                        = 6x 10-5 H