Practicing Success
In the figure, if ∠A = 100° then ∠C = ? |
50° 90° 80° 100° |
80° |
\(\angle\)A = 100 As we know, \(\angle\)A + \(\angle\)C = 180 [opposite angles of cyclic quadrilateral] = 100 + \(\angle\)C = 180 = \(\angle\)C = 180 - 100 = 80 Therefore, \(\angle\)C is \({80}^\circ\). |