Practicing Success
A and B working alone can complete a work in 8 days and 12 days. respectively. They started working together, but A left 2 days before completion of the work. In how many days was the work completed ? |
6 5 8 10 |
6 |
A = 8 days, B = 12 days, ⇒ Last 2 days work done by B = 2 x 2 = 4 units ..(Efficiency × Days = Work) ⇒ Remaining work = 24 - 4 =20 units. ⇒ Work done by A + B = 3 + 2 = 5 units. ⇒ \(\frac{Remaining work}{5}\) + last 2 days = \(\frac{20}{5}\) + 2 = 6 days Therefore, the work was completed in 6 days. |