12 men and 9 women can finish the work in 10 days. 4 men and 12 women can finish the same work in 15 days, if 10 men start the work and worked for 6 days and after that 'x' men and 'x+2' women join the work and total work finished in 21 days, find the value of 'x'.
Answer & explanation
Correct answer: option 1
(12 M + 9 W) × 10 = (4 M + 12 W) × 15
120 M + 90 W = 60 M + 180 W
60 M = 90 W
2 M = 3 W ⇒ \(\frac{M}{W}\) = \(\frac{3}{2}\)
⇒ Total work = (12 × 3 + 9 × 2) × 10 = 540
10 men worked for 6 days, hence work done = 10 × 3 × 6 = 180
Remaining work = 540 - 180 = 360
ATQ,
[ xM + (x+2) W] × 15 = 360
3 x + (x + 2) × 2 = 24
5x + 4 = 24
x = 4