The capacitance of a parallel plate capacitor does not depend on

The correct answer is Option (2) → charges on the plates

The capacitance of a parallel plate capacitor is fixed by its geometry and the medium between the plates:

    \( \displaystyle C = \frac{K\varepsilon_0 A}{d} \)

It contains the plate area A (size of the plates), the separation d and the dielectric constant K (material between the plates), but not the charge. If the charge Q is doubled, the potential difference V also doubles, so the ratio \( C = Q/V \) stays the same.

NCERT (2026-27):
Summary – “… A capacitor is a system of two conductors separated by an insulator. Its capacitance is defined by \( C = Q/V \), where \( Q \) and \( -Q \) are the charges on the two conductors and \( V \) is the potential difference between them. C is determined purely geometrically, by the shapes, sizes and relative positions of the two conductors.”