The value of $\sqrt{cos60°cos30°

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

The value of $\sqrt{cos60°cos30°-sin60°sin30°}$ is :

Options:

$\frac{\sqrt{3}}{2}$

$\frac{1}{\sqrt{2}}$

Correct Answer:

Explanation:

$\sqrt{cos60°cos30°-sin60°sin30°}$

{ Using formula :- cos ( A + B ) = cosA . cosB - sinA . sinB }

= $\sqrt{cos(60°+30°)}$

= $\sqrt{cos(90°)}$

= 0