There are the batting average of 50 innings of a player was 60 runs. His highest score exceed by lowest score by 194 runs. If this two innings are excluded, the average of 48 innings becomes 58 runs. Find the higher score of the player. |
210 128 205 195 |
205 |
Innings Average Total Runs 50 × 60 = 3000 48 × 58 = 2784 ← excluding two innings Runs of two innings = 216 Difference of two innings = 194 Let, lowest score = x Highest score = 194 + x 2x + 194 = 216 x = 11 Highest score = 194+ 11 = 205 |