There are the batting average of 50 innings of a player was 60 runs. His highest score exceed by lowest score by 194 runs. If this two innings are excluded, the average of 48 innings becomes 58 runs. Find the higher score of the player.
Answer & explanation
Correct answer: option 3
Innings Average Total Runs
50 × 60 = 3000
48 × 58 = 2784 ← excluding two innings
Runs of two innings = 216
Difference of two innings = 194
Let, lowest score = x
Highest score = 194 + x
2x + 194 = 216
x = 11
Highest score = 194+ 11 = 205