Practicing Success
The equation of perpendicular from the point (1, 0, 1) to the plane x - y + z = 4 is |
$\frac{x-1}{2}=\frac{y}{-1}=\frac{z-1}{2}$ $\frac{x-1}{1}=\frac{y}{-1}=\frac{z-1}{1}$ $\frac{x-1}{1}=\frac{y-3}{-1}=\frac{z-2}{1}$ $\frac{x-1}{2}=\frac{y}{1}=\frac{z-1}{3}$ |
$\frac{x-1}{1}=\frac{y}{-1}=\frac{z-1}{1}$ |
The correct answer is Option (3) → $\frac{x-1}{1}=\frac{y}{-1}=\frac{z-1}{1}$ Point: $P(1, 0, 1)$ plane: $x - y + z = 4$ Normal vector = $\hat i-\hat j+\hat k=\vec n$ so line is perpendicular to plane in direction of $\vec n$ and passes through P line: $\frac{x-1}{1}=\frac{y}{-1}=\frac{z-1}{1}$ |