If the lines $\frac{1-x}{3}=\frac{2 y-4}{4 K}=\frac{z-3}{2}$ and $\frac{x-1}{3 K}=\frac{1-y}{-1}=\frac{6-z}{5}$ are perpendicular, then the value of K is:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $-\frac{10}{7}$
lines are perpendicular
$⇒(-3\hat i+\frac{4K}{2}\hat j+2\hat k).(3K\hat i+\hat j-5\hat k)=0$
$⇒-9K+2K-10=0$
$7K=-10$
$K=-\frac{10}{7}$