Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Applications of Derivatives

Question:

Find the rate of change of the area of a circle per second with respect to its radius r when r = 2.5 cm.

Options:

$4\pi$

$5\pi$

$2\pi$

$10\pi$

Correct Answer:

$5\pi$

Explanation:

The correct answer is Option (2) → $5\pi$

A, Area of circle = $\pi r^2$

$⇒\frac{dA}{dr}=2\pi r$

$⇒\left.\frac{dA}{dr}\right|_{r=2.5}=2\pi(2.5)$

$=5\pi$