O is the center of a circle. Two tangents AP and AQ are drawn on the circumference from an external point A. If ∠POQ = 128°, then ∠PAQ is?
Answer & explanation
Correct answer: option 3
∠PAQ = 180° - 128° = 52°
O is the center of a circle. Two tangents AP and AQ are drawn on the circumference from an external point A. If ∠POQ = 128°, then ∠PAQ is?
Correct answer: option 3
∠PAQ = 180° - 128° = 52°