If $ ( x - \frac{1}{x}) = \frac{7}{3}$, what is the value of $4(x^3 - \frac{1}{x^3})$ ?

$19\frac{20}{27}$ $19\frac{19}{27}$ $19\frac{7}{9}$ $19\frac{2}{3}$

$19\frac{19}{27}$