Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Numbers, Quantification and Numerical Applications

Question:

Disha can run 1 km in 2 minutes 30 seconds and Amisha can cover the same distance in 2 minutes 40 seconds. Disha can beat Amisha by distance ___________ .

Options:

65.5 m

64.5 m

63.5 m

62.5 m

Correct Answer:

62.5 m

Explanation:

$\text{Distance}=1\text{ km}=1000\text{ m}.$

$\text{Time taken by Disha}=2\text{ min }30\text{ s}=150\text{ s}.$

$\text{Time taken by Amisha}=2\text{ min }40\text{ s}=160\text{ s}.$

$\text{Speed of Disha}=\frac{1000}{150}=\frac{20}{3}\text{ m/s}.$

$\text{Speed of Amisha}=\frac{1000}{160}=\frac{25}{4}\text{ m/s}.$

$\text{Distance covered by Amisha in }150\text{ s}=\frac{25}{4}\times150=937.5\text{ m}.$

$\text{Distance by which Disha beats Amisha}=1000-937.5=62.5\text{ m}.$

$\text{Disha beats Amisha by }62.5\text{ m}.$