CUET Preparation Today
CUET
Physics
Current Electricity
In the circuit shown in figure, the ratio of currents i1 / i2 is
2
8
0.5
4
i1 = 4A
Further dividing 2A across different resistors we can find that
$i_2=\frac{2}{4}=\frac{1}{2} A$
Hence, $\frac{i_1}{i_2}=\frac{8}{1}$
