What is the value of $\frac{3}{5}(sec^220^o - cot^270^o)$?

4/3 5/3 2/5 3/5

3/5

$\frac{3}{5}(sec^220^o - cot^270^o)$ { using , secA = cosecB  Iff A + B = 90º  } = $\frac{3}{5}(cosec^270^o - cot^270^o)$ { We know,  cosec²A - cot²A = 1 } = $\frac{3}{5}(1)$ = $\frac{3}{5}$