What is the value of $\frac{3}{5}(sec^220^o - cot^270^o)$?
Answer & explanation
Correct answer: option 4
$\frac{3}{5}(sec^220^o - cot^270^o)$
{ using , secA = cosecB Iff A + B = 90º }
= $\frac{3}{5}(cosec^270^o - cot^270^o)$
{ We know, cosec²A - cot²A = 1 }
= $\frac{3}{5}(1)$
= $\frac{3}{5}$