If $sinθ = \frac{3}{5}$, then what is tan θ?

$\frac{3}{5}$ $\frac{4}{3}$ $\frac{4}{5}$ $\frac{3}{4}$

$\frac{3}{4}$

$sinx = \frac{3}{5}$        = $\frac{P}{H}$ P = 3, H = 5 B = $\sqrt{H^2-P^2}$    = $\sqrt{5^2-3^2}$ = 4 $tanx = \frac{P}{B}$           = $\frac{3}{4}$