If $sinθ = \frac{3}{5}$, then what is tan θ?
Answer & explanation
Correct answer: option 4
$sinx = \frac{3}{5}$
= $\frac{P}{H}$
P = 3, H = 5
B = $\sqrt{H^2-P^2}$
= $\sqrt{5^2-3^2}$ = 4
$tanx = \frac{P}{B}$
= $\frac{3}{4}$
If $sinθ = \frac{3}{5}$, then what is tan θ?
Correct answer: option 4
$sinx = \frac{3}{5}$
= $\frac{P}{H}$
P = 3, H = 5
B = $\sqrt{H^2-P^2}$
= $\sqrt{5^2-3^2}$ = 4
$tanx = \frac{P}{B}$
= $\frac{3}{4}$