CUET Preparation Today
If $sinθ = \frac{3}{5}$, then what is tan θ? |
$\frac{3}{5}$ $\frac{4}{3}$ $\frac{4}{5}$ $\frac{3}{4}$ |
$\frac{3}{4}$ |
$sinx = \frac{3}{5}$ = $\frac{P}{H}$ P = 3, H = 5 B = $\sqrt{H^2-P^2}$ = $\sqrt{5^2-3^2}$ = 4 $tanx = \frac{P}{B}$ = $\frac{3}{4}$
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