The order and degree of differential equation $\left[1+\left(\frac{d y}{d x}\right)^2\right]^2=\frac{d^2 y}{d x^2}$ respectively, are
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) - 2, 1
highest order leave with highest degree → $\frac{d^2y}{dx^2}$
order = 2
degree = 1