The values of van't Hoff factors for \(CaCl_2\), \(Na_2SO_4\) and \(KCl\) respectively are:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 3, 3, 2
For a strong electrolyte that dissociates completely, the van’t Hoff factor i equals the number of ions given by one formula unit:
\( \ce{CaCl2} \) → \( \ce{Ca^{2+}} \) + \( \ce{2Cl^{-}} \): i = 3
\( \ce{Na2SO4} \) → \( \ce{2Na^{+}} \) + \( \ce{SO4^{2-}} \): i = 3
KCl → \( \ce{K^{+}} \) + \( \ce{Cl^{-}} \): i = 2