The de Broglie wavelength of a photon is twice the de Broglie wavelength of an electron. The speed of electron is 0.01 c, then :
Answer & explanation
Correct answer: option 3
Use :
\(\lambda\)e = \(\frac{h}{m_e v_e}\)
Ee = \(\frac{1}{2}\) meve2
Ee = \(\frac{h^2}{2\lambda_e^2 m_e}\)