Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Dual Nature of Radiation and Matter

Question:

The de Broglie wavelength of a photon is twice the de Broglie wavelength of an electron. The speed of electron is 0.01 c, then : 

Options:

Ee/Ep = 10-4

pe/mec =  10-4

Ee/Ep = 10-2

None of these.

Correct Answer:

Ee/Ep = 10-2

Explanation:

Use :

\(\lambda\)e = \(\frac{h}{m_e v_e}\) 

Ee = \(\frac{1}{2}\) meve2

Ee = \(\frac{h^2}{2\lambda_e^2 m_e}\)