Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Vectors

Question:

Find |\(\vec{a}\)| and |\(\vec{b}\)|  if (\(\vec{a}\)+ \(\vec{b}\) ).(\(\vec{a}\) -\(\vec{b}\)) = 8 and |\(\vec{a}\)| = 8( |\(\vec{b}\)|)

Options:

|\(\vec{b}\)| = (2√2)/(3√7)

|\(\vec{a}\)| = -(16√2)/(3√7)

 

|\(\vec{b}\)|= (2√2)/(3√7)

|\(\vec{a}\)| = (16√5)/(3√7)

 

|\(\vec{b}\)| = -(2√2)/(3√7)

|\(\vec{a}\)| = (16√2)/(3√7)

 

|\(\vec{b}\)| = (2√2)/(3√7)

 |\(\vec{a}\)|= (16√2)/(3√7)

 

Correct Answer:

|\(\vec{b}\)| = (2√2)/(3√7)

 |\(\vec{a}\)|= (16√2)/(3√7)

 

Explanation:

given that  (\(\vec{a}\)+ \(\vec{b}\)).(\(\vec{a}\)-\(\vec{b}\) ) = 8 

⇒ \(\vec{a}\).\(\vec{a}\)  - \(\vec{a}\).\(\vec{b}\) + \(\vec{b}\).\(\vec{a}\)  -\(\vec{b}\) .\(\vec{b}\)  =8

⇒ |\(\vec{a}\)|2 - |\(\vec{b}\)|2 =8  

it is also given  |\(\vec{a}\)|= 8(\(\vec{b}\))

⇒ {8(|\(\vec{b}\)|2) - (|\(\vec{b}\)|2)} =8

⇒ (|\(\vec{b}\)|2) = 8/63

⇒ (|\(\vec{b}\)|) = (2√2)/(3√7)

⇒ (|\(\vec{a}\)|)= (16√2)/(3√7)