Find $\int_{0}^{2/3}\frac{1}{4+9x^2}dx$1$\pi/2$203$\pi/12$4$\pi/4$Answer & explanation+Correct answer: option 3$I=\int_{0}^{2/3}\frac{1}{4+9x^2}dx=\int_{0}^{2/3}\frac{1}{2^2+(3x)^2}dx={1/3/}\int_{0}^2\frac{1}{2^2+z^2}dz=\pi/12$
