Practicing Success
Practicing Success
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| Find $\int_{0}^{2/3}\frac{1}{4+9x^2}dx$ |
$\pi/2$ 0 $\pi/12$ $\pi/4$ |
| $\pi/12$ |
| $I=\int_{0}^{2/3}\frac{1}{4+9x^2}dx=\int_{0}^{2/3}\frac{1}{2^2+(3x)^2}dx={1/3/}\int_{0}^2\frac{1}{2^2+z^2}dz=\pi/12$ |
