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Find the value of x if \(\begin{vmatrix}3x & 5 \\2 & x \end{vmatrix}\) = \(\begin{vmatrix}4 & 5 \\13 & -5 \end{vmatrix}\) |
5 -5 Both (a) and (b) None of the above |
Both (a) and (b) |
\(\begin{vmatrix}3x & 5 \\2 & x \end{vmatrix}\) = \(\begin{vmatrix}4 & 5 \\13 & -5 \end{vmatrix}\) \(⇒3 { x }^{ 2 } -10 =-20- 65\) so \(3 { x }^{ 2 } = -75\) \({ x }^{ 2 } = -25\) so $x=±5$ |
