For a microscopic object Δx is zero than what will be Δv according to Heisenberg's uncertainty principle?

Infinite

The correct answer is option 2. Infinite.

According to Heisenberg's uncertainty principle,

Δx . Δp ≥ \(\frac{h}{4π}\)

Δx . mΔv ≥ \(\frac{h}{4π}\)

If Δx = 0

Δv ≥ \(\frac{h}{4πmΔx}\)

Δv ≥ \(\frac{h}{4πm×0}\) 

Δv = Infinite