For a microscopic object Δx is zero than what will be Δv according to Heisenberg's uncertainty principle?
Answer & explanation
Correct answer: option 2
The correct answer is option 2. Infinite.
According to Heisenberg's uncertainty principle,
Δx . Δp ≥ \(\frac{h}{4π}\)
Δx . mΔv ≥ \(\frac{h}{4π}\)
If Δx = 0
Δv ≥ \(\frac{h}{4πmΔx}\)
Δv ≥ \(\frac{h}{4πm×0}\)
Δv = Infinite