Practicing Success
Practicing Success
CUET Preparation Today
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b |
$\text{Distance of point A from origin is } r_1 = \sqrt{x^2 + y^2} = 2$ $\text{Distance of point B from origin is } r_2 = \sqrt{x^2 + y^2} = 2$ $\text{Potential of both A and B are same so potential difference is zero.}$ |
