If $\begin{bmatrix}2x+3 & 3y& 3\\y+1& 2x-z& -1\\3z+1& 2& 5\end{bmatrix}=\begin{bmatrix}7 & -9 & 3\\-2 & -4 & -1\\25 & 2 & 5\end{bmatrix},$ then the values of x, y and z are :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $x=2, y=-3, z=8$
$2x+3=7$
$⇒2x=4$
$⇒x=2$
$3y=-9$
$⇒y=-3$
$3z+1=25$
$⇒3z=24$
$⇒z=8$