The list price of a motorcycle is 20% more than its cost price. It is sold at a discount of 30%. Find the dealer's loss percentage.

16%

Let the cost price = 100

Markup = 20%

then the marked price of the article = 120

discount % = 30%

Then the selling price = 70% of the marked price

SP = 70% of 120 = 84

Then the loss% = ( 100 - 84) × \(\frac{100}{100}\) = 16%