Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Inorganic: D and F Block Elements

Question:

The blue colour is produced on adding H2O2 in acidified K2Cr2O7 solution is due to the formation of which of the following?

Options:

CrO5

Cr2O3

CrO42-

CrO3

Correct Answer:

CrO5

Explanation:

The reaction between acidified K2Cr2O7 and H2O2 is given as:

K2Cr2O+ 4H2O2 + H2SO4 → 2CrO5 + K2SO4 + 5H2

The deep blue colour obtained is due to formation of CrO5; which fades away and compound gets decomposed  to Cr3+ and O2(g) in the aqueous solution readily. So, ether is added to extract CrO5 because it will remain stable in such medium.