Given below is an arrangement of resistors in the form of a Wheatstone Bridge. Find the value of x so that the galvanometer holds zero reading.
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 2 Ω 
for $G=0$
$\frac{16}{X}=\frac{4}{1/2}$ [Property of Wheatstone Bridge]
$\frac{16}{X}=8$
$X=\frac{16}{8}=2Ω$