CUET Preparation Today
Given below is an arrangement of resistors in the form of a Wheatstone Bridge. Find the value of x so that the galvanometer holds zero reading.
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1 Ω 2 Ω 3 Ω 4 Ω |
2 Ω |
The correct answer is Option (2) → 2 Ω for $G=0$ $\frac{16}{X}=\frac{4}{1/2}$ [Property of Wheatstone Bridge] $\frac{16}{X}=8$ $X=\frac{16}{8}=2Ω$ |
