\(\int e^{x}\left[f(x)+f^{\prime}(x)\right]dx\) equals

\(e^{x} f(x)+C\) \(e^{x}f^{\prime}(x)+C\) \(e^{x}f(x)+f^{\prime}(x)+C\) None

\(e^{x} f(x)+C\)

Integration by parts