The primary voltage and primary current of a transformer are 220 V and 10 A. The ratio of the number of turns on the secondary coil to the number of turns on the primary coil is 2:1. The values of voltage and current at the output are

440 V and 5 A

The correct answer is Option (3) → 440 V and 5 A

Given:

Primary voltage $V_p = 220 \, \text{V}$

Primary current $I_p = 10 \, \text{A}$

Turns ratio $\frac{N_s}{N_p} = \frac{2}{1}$

Transformer equations:

$\frac{V_s}{V_p} = \frac{N_s}{N_p} \Rightarrow V_s = V_p \cdot \frac{N_s}{N_p}$

$V_s = 220 \cdot \frac{2}{1} = 440 \, \text{V}$

$\frac{I_s}{I_p} = \frac{N_p}{N_s} \Rightarrow I_s = I_p \cdot \frac{N_p}{N_s}$

$I_s = 10 \cdot \frac{1}{2} = 5 \, \text{A}$