An ac source of variable angular frequency and constant amplitude is connected in series with a capacitance C and an electric bulb of resistance R. When angular frequency is increased then:

the bulb glow brighter

The correct answer is Option (3) → the bulb glow brighter

When angular frequency $(ω)$ increases, the capacitive reactance also decreases.

$X_C=\frac{1}{ωC}$

Due to this, impedance of the circuit decreases.

$Z=\sqrt{R^2+{X_C}^2}$

Since the current increases and the impedance decreases, the power initially increases.