An ac source of variable angular frequency and constant amplitude is connected in series with a capacitance C and an electric bulb of resistance R. When angular frequency is increased then:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → the bulb glow brighter
When angular frequency $(ω)$ increases, the capacitive reactance also decreases.
$X_C=\frac{1}{ωC}$
Due to this, impedance of the circuit decreases.
$Z=\sqrt{R^2+{X_C}^2}$
Since the current increases and the impedance decreases, the power initially increases.