CUET Preparation Today
CUET
General Test
Quantitative Reasoning
Trigonometry
If cosx=pq and 0° < x < 90°, then the value of tanx is :
√q2−p2q
q√q2−p2
p√p2−q2
√q2−p2p
cosx = pq
{ cosx = BH }
B² + P² = H²
p² + P² = q²
P = \sqrt {q² - p² }
Now,
tanx
= \frac{P }{B}
= \(\frac{\sqrt {q² - p² }\ }{p}\)