If $cosx =\frac{p}{q}$ and 0° < x < 90°, then the value of tanx is :
Answer & explanation
Correct answer: option 4
cosx = \(\frac{p }{q}\)
{ cosx = \(\frac{B }{H}\) }
B² + P² = H²
p² + P² = q²
P = \(\sqrt {q² - p² }\)
Now,
tanx
= \(\frac{P }{B}\)
= \(\frac{\sqrt {q² - p² }\ }{p}\)