A rod AB is moved with a speed of 1 m/s in magnetic field of strength B = 1 T as shown in the figure. If the length of rod is 2 cm, the emf produced is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 0.02 V
A rod of length l moving with speed v at right angles to a field B has a motional emf \( \varepsilon = Blv \). Here the rod, its velocity and the field are mutually perpendicular.
Convert the length: \( l = 2\,\mathrm{cm} = 0.02\,\mathrm{m} \).
\( \varepsilon = Blv = 1\,\mathrm{T}\times0.02\,\mathrm{m}\times1\,\mathrm{m\,s^{-1}} \)
\( \varepsilon = 0.02\,\mathrm{V} \)