Target Exam

CUET

Subject

Physics

Chapter

Electromagnetic Induction

Question:

A rod AB is moved with a speed of 1 m/s in magnetic field of strength B = 1 T as shown in the figure. If the length of rod is 2 cm, the emf produced is

Options:

2 V

0.02 V

0.2 V

zero

Correct Answer:

0.02 V

Explanation:

The correct answer is Option (2) → 0.02 V

The emf induced in the rod is -

$ε=Blv$

where,

B = Magnetic field = 1 T

$l$ = length of the rod = 2 cm = 0.02 m

v = velocity = 1 m/s

$∴ε=1×0.02×1$

$=0.02V$