Solve the following LPP graphically: Maximize $Z = x + 3y$, subject to the constraints: $x + 2y \le 200$, $x + y \le 150$, $y \le 75$, $x, y \ge 0$.

$Z = 275$ at $(50, 75)$

The correct answer is Option (4) → $Z = 275$ at $(50, 75)$ ##

Maximize $Z = x + 3y$ subject to the constraints:

• $x + 2y \le 200$
• $x + y \le 150$
• $y \le 75$
• $x, y \ge 0$

Now, $x + 2y = 200$

 $x + y = 150$

 $y = 75$

Corner points and evaluation of $Z$:

Maximum value of $Z = 275$ at $x = 50, y = 75$