A is thrice as efficient as B. A takes 24 days less than B to complete a work. If they work together, in how many days, will the work be completed?
Answer & explanation
Correct answer: option 1
Given,
A is thrice as efficient as B.
A : B = 3 : 1 (Efficiency)
Efficiency α \(\frac{1}{Time}\)
⇒ A : B = 1 : 3 (Time)
⇒ (3 -1)x = 24 days
⇒ 2x = 24
⇒ x = 12 days,
⇒ Therefore, total work = 3 x 12 = 36 units, ..(Efficiency × Days = Total work)
⇒ Time required by A + B to complete the work = \(\frac{36}{4}\) = 9 days, ..(\(\frac{Work}{Efficiency}\) = Time)