CUET Preparation Today
A magnet of magnetic moment $50\hat iAm^2$ is placed along the X-axis in a magnetic field $\vec B=(0.5\hat i+3.0\hat j) T$. The torque acting on it is |
$175\hat k\, Nm$ $150\hat k\, Nm$ $75\hat k\, Nm$ $25\sqrt{37}\hat k\, Nm$ |
$150\hat k\, Nm$ |
$\tau = \vec{m}\times \vec{B} = 150\hat{k} N-m$ The correct answer is Option (2) → $150\hat k\, Nm$ |
