If \(f(x) = 27x^3\) and \(g(x) = (x)^{\frac{1}{3}}\), then gof(x) is:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → \(3x\)
In the composition gof, f acts first and g acts on its output:
\(g\big(f(x)\big) = g\left(27x^3\right)\)
\(= \left(27x^3\right)^{\frac{1}{3}}\)
\(= 3x\)
since \(27 = 3^3\).