Find the equation of a curve whose tangent at any point on it, different from origin, has slope y + (y/x).
Answer & explanation
Correct answer: option 3
dy/dx = y + (y/x)
dy/y = (1+1/x)dx and then integrate to obtain :
y = kx.ex
Find the equation of a curve whose tangent at any point on it, different from origin, has slope y + (y/x).
Correct answer: option 3
dy/dx = y + (y/x)
dy/y = (1+1/x)dx and then integrate to obtain :
y = kx.ex