The solution of LPP :
Min.(z)= 100x+ 400y
s.t. $x+2y ≥8$
$2x+5y≤20$
$x≥0, y≥0.$
occurs at :
Answer & explanation
Correct answer: option 3
Given LPP:
Minimize $Z=100x+400y$
Subject to
$x+2y\ge 8$
$2x+5y\le 20$
$x\ge 0,\;y\ge 0$
Thus feasible corner points are $(8,0)$ and $(0,4)$.
Evaluate $Z$:
$Z(8,0)=100(8)+400(0)=800$
$Z(0,4)=100(0)+400(4)=1600$
Minimum value is $800$.
final answer: minimum occurs at $(8,0)$