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CUET
-- Mathematics - Section B2
Linear Programming
The solution of LPP :
Min.(z)= 100x+ 400y
s.t. $x+2y ≥8$
$2x+5y≤20$
$x≥0, y≥0.$
occurs at :
$x=0, y = 4 $
$x=4, y = 8 $
$x=8, y = 0 $
$x=10, y = 0 $