The value of $2 y-3 x$, if $2\left[\begin{array}{rr}x & 5~~~ \\ 7 & y-3\end{array}\right]+\left[\begin{array}{rr}3 & -4 \\ 1 & 2\end{array}\right]=\left[\begin{array}{rr}7 & 6 \\ 15 & 14\end{array}\right]$ is:

12

The correct answer is Option (1) - 12

$2\left[\begin{array}{rr}x & 5~~~ \\ 7 & y-3\end{array}\right]+\left[\begin{array}{rr}3 & -4 \\ 1 & 2\end{array}\right]=\left[\begin{array}{rr}7 & 6 \\ 15 & 14\end{array}\right]$

$⇒2\begin{bmatrix}x&5\\7&y-3\end{bmatrix}=\begin{bmatrix}4&10\\14&12\end{bmatrix}$

$x=\frac{4}{2},y=\frac{18}{2}$

$2y-3x=\frac{36-12}{2}=12$