Practicing Success
If cos B $ =\frac{5}{9}$, then what is the value of cosec B ? |
$\frac{9}{2\sqrt{14}}$ $\frac{9}{\sqrt{14}}$ $\frac{4}{\sqrt{14}}$ $\frac{5}{\sqrt{14}}$ |
$\frac{9}{2\sqrt{14}}$ |
cosB = $\frac{base}{hypotenuse} = $\frac{5}{9}$ In a triangle ABC, Base = 5 Hypotenuse = 9 Perpendicular = $\sqrt{hyp.^2 - base^2}$ = $\sqrt{9^2 - 5^2}$ = $\sqrt{81 - 25}$ = $\sqrt{56}$ = 2$\sqrt{14}$ cosecB = $\frac{hypotenuse}{perpendicular}$ = $\frac{9}{2\sqrt{14}}$ |