Identify the correct sequence of structures formed during spermatogen…

The correct answer is Option (4) → (C), (B), (D), (A)

(C) Spermatogonia — first. These are the immature male germ cells on the inside wall of the seminiferous tubules. They are diploid and multiply by mitosis.

(B) Secondary spermatocytes — second. Some spermatogonia become primary spermatocytes, a stage the question leaves out. The first meiotic division of a primary spermatocyte gives two haploid secondary spermatocytes.

(D) Spermatids — third. The second meiotic division turns each secondary spermatocyte into two spermatids, so one primary spermatocyte gives four.

(A) Spermatozoa — last. Spermatids change shape into sperms (spermatozoa) by spermiogenesis, and the sperms are then released from the tubules.

Note: A similar question was also asked in CUET (UG) 2026 on 22-05-2026 (Slot 2), on 20-05-2026 (Slot 2) and on 14-05-2026 (Slot 1), and in CUET (UG) 2025 on 28-05-2025 (Slot 1), on 20-05-2025 (Slot 2), on 20-05-2025 (Slot 1) and on 15-05-2025 (Slot 1).

NCERT Extract:
Gametogenesis – “… The spermatogonia (sing. spermatogonium) present on the inside wall of seminiferous tubules multiply by mitotic division and increase in numbers. Each spermatogonium is diploid and contains 46 chromosomes. Some of the spermatogonia called primary spermatocytes periodically undergo meiosis. A primary spermatocyte completes the first meiotic division (reduction division) leading to formation of two equal, haploid cells called secondary spermatocytes, which have only 23 chromosomes each. The secondary spermatocytes undergo the second meiotic division to produce four equal, haploid spermatids (Figure 2.5). … The spermatids are transformed into spermatozoa (sperms) by the process called spermiogenesis.”