Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Index Numbers and Time Based Data

Question:

The value of the Euler Totient function $\phi (n)$ at 400 is :

Options:

96

60

120

160

Correct Answer:

160

Explanation:

The correct answer is Option (4) → 160

$400=2^4×5^2$

$\phi(n)=n\left(1-\frac{1}{p_1}\right)\left(1-\frac{1}{p_2}\right)....\left(1-\frac{1}{p_n}\right)$

$\phi(400)=400×\left(1-\frac{1}{2}\right)\left(1-\frac{1}{5}\right)$

$=400×\frac{1}{2}×\frac{4}{5}=160$