Two numbers are in the ratio of 3 : 5. If 9 is subtracted from each, the ratio becomes 12 : 23. Find the greater number. |
55 65 57 63 |
55 |
The correct answer is Option (1) → 55 Step 1: Let the numbers be $3x \text{ and } 5x$ Step 2: Condition after subtracting 9 $\frac{3x - 9}{5x - 9} = \frac{12}{23}$ Step 3: Cross-multiply $23(3x - 9) = 12(5x - 9)$ $69x - 207 = 60x – 108$ $69x - 60x = -108 + 207$ $9x=99$ $x = 11$ Step 4: Find the numbers $3x = 3 \cdot 11 = 33 \quad (\text{smaller})$ $5x = 5 \cdot 11 = 55 \quad (\text{greater})$ |