Practicing Success
Let $f(x) =x^n$, n being a non-negative integer. The value of n for which the equality f'(x + y) = f'(x) + f'(y) is valid for all x, y > 0 is |
0, 1 1, 2 2, 4 none of these |
none of these |
We have, $f(x)=x^n \Rightarrow f(x+y)=(x+y)^n \Rightarrow f'(x+y)=n(x+y)^{n-1}$ Also, $f'(x)=n x^{n-1}$ and $f'(y)=n y^{n-1}$ ∴ $f'(x+y)=f'(x)+f'(y)$ $\Rightarrow n(x+y)^{n-1}=n . x^{n-1}+n . y^{n-1}$ $\Rightarrow (x+y)^{n-1}=x^{n-1}+y^{n-1}$ Clearly, this is true for n = 2 only. |