Practicing Success
If $f (2) = g(2)$ and $f'(2) = a, g'(2) = 2a$, then $\underset{x→2}{\lim}\frac{f(x)-g(x)}{x-2}$ is equal to |
1 a -a none of these |
-a |
$\underset{x→2}{\lim}\frac{f(x)-g(x)}{x-2}=\underset{x→2}{\lim}\frac{f'(x)-g'(x)}{1}=f'(2)-g'(2)=a-2a=-a$ |