Practicing Success
C1, C2 and C3 can do a work alone in 10, 12 and 15 days respectively. All three of them began the work together but C2 left 2 days before the completion of the work. In how many days was the work completed? |
(18/5) days (17/3) days 5 days (12/5) days |
5 days |
Total work = LCM of 10, 12, 15 total efficiency of C1, C2, C3 = 6 + 5 + 4 = 15 Work = Time x Efficiency Let the time taken for the total work was 'x', then C1, C3 worked for 'x' days and C2 worked for 'x-2' days, Using the formula, 6x + 5(x-2) + 4x = 60 ⇒ 6x + 5x + 4x - 10 = 60 ⇒ 14x = 70 ⇒ x = 5 Thus, it takes 5 days to complete the work. |