If B is a non-singular matrix and A is a square matrix, then $det (B^{-1}AB)$ =
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $det(A)$
$|B^{-1}AB|=|B^{-1}||A||B|$ $[|AB|=|A||B|]$
$=\frac{1}{|B|}|A||B|$ $[|B^{-1}|=\frac{1}{|B|},|B|≠0]$
$=|A|$