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The corner points of the feasible region determined by the system of linear constraints are (0, 4), (4, 0), (5, 0), (5, 3), (3, 5), (0, 5). Let $Z=x-7y+80.$ The minimum value of Z occurs at : |
(5, 0) (0, 5) (3, 5) (5, 3) |
(0, 5) |
The correct answer is Option (2) → (0, 5) $Z(x,y)=x-7y+80$ Minimum occurs at $Z(0,5)$. $Z(0,5)=0-7×5+80$ $=45$ |
