CUET Preparation Today
Evaluate the integral: $\int\limits_{2}^{3} x^2 \, dx$ |
$\frac{7}{3}$ $9$ $\frac{19}{3}$ $\frac{26}{3}$ |
$\frac{19}{3}$ |
The correct answer is Option (3) → $\frac{19}{3}$ Let $I = \int\limits_{2}^{3} x^2 \, dx$. Since $\int x^2 \, dx = \frac{x^3}{3} = F(x)$, Therefore, by the second fundamental theorem, we get $I = F(3) - F(2) = \frac{27}{3} - \frac{8}{3} = \frac{19}{3} \text{}$ |
